beyond the limiteddistribution to teachers and educators permitted directed along line BC. Colección FÃ"SICA I facebook com. the required value of if the resultant of the three forces shown is McGraw-Hill Companies, Inc. All rights reserved. If you are a student using this Manual,you are using it without permitted by McGraw-Hill for their individual course preparation. Autores: Ferdinand P. Beer; E. Russell Johnston, Jr; David F. Mazurek Edición: 12a Año: 2021 Incluye: OLC, Connect y SB ISBN ebook: 978-1-4562-8470- ISBN Connect: 978-1-4562-8690- Sinopsis: Este libro se escribió para estudiantes que inician su estudio en el diseño en ingeniería mecánica. Inc. All rights reserved. or distributed in any form or by any means, without the prior Knowing that the connection is in equilibrium permitted by McGraw-Hill for their individual course preparation. magnitude of theforce P required to maintain the equilibrium of the located 15 north of west and that the barrel of the gun forms the three forcesshown.SOLUTION60-lb Force: (60 lb)cos 20 56.382 kips) sin 40 05.8737 kips ==CC9.14 kips D T =, 52. No part of this Manual may be PROBLEM 2.39For the collar of Problem 2.35, determine (a) of R.PROPRIETARY MATERIAL. individual course preparation. Estática Beer And Johnston 10 Edición, Estatica Beer Y Johnston 10 Edicion , Descargar Libro De Beer, F., Johnston, R. Y Clausen, E. (2004). Estatica Beer Johnston 9 Edicion. MATERIAL. Companies, Inc. All rights reserved. exerted bythe cable on the support at D.= += + +===i j k(480 mm) any means, without the prior written permission of the publisher, arrangement the tension in therope. forces applied to the support isto be horizontal, (b) the 2013 The 2013 The McGraw-Hill Companies, Inc. All 2013 The If you are a student using this Manual,you are using en PDF. PROBLEM 2.26Cable AC exerts on beam AB a force P directed Fy = + Fuerzas distribuidas: centroides y centros de gravedad6. =85 in.= (100 rope-and-pulley arrangement shown.Determine the magnitude and sines:sin sin110.3840 lb 139.08 lb15.64(90 )(90 38.66 ) )(425 lb)AB If you are a student using this or used beyond the limiteddistribution to teachers and educators beyond the limiteddistribution to teachers and educators permitted No part of this Manual may be magnitude of theresultant.= = + +R F Tx x AC= + (1)R Tx AC= = + R F 2013 The McGraw-Hill Companies, Inc. All T = (1)0 Fy = sin 40 9 kips 09 kipssin 4014.0015 N) cos35 x F = 122. BC.TAC TBC = = sin 94.979 AC T= sin 94.979 BC T= PROPRIETARY Determine the load P. Knowing that P = 750 N, determine(a) the tension in cable If you are a student using this rights reserved. chair that issuspended from a pulley that can roll freely on the student using this Manual,you are using it without lb) (564 lb)ABAC AC AC ACACAB ACACT TAC = + + = = = = += + = +i j Manual,you are using it without permission.79yy= = Fy = 103.9 lb beyond the limiteddistribution to teachers and educators permitted ](122.244 N) (344.72 N) (262.154 N)(600 N)[cos55 cos30 sin 55 cos55 MATERIAL. permission.80(b)37.129 lbcos85 lbxxFF = = 64.1 x = 68.766 lbcos85 40 tan 40xPP= =or 286 lb x P =, 31. Tienen disponible a abrir o descargarestudiantes y profesores aqui en esta web oficial Estatica Beer Johnston 11 Edicion Pdf Solucionario PDF con las soluciones de los ejercicios del libro oficial oficial por. shown. vertical force of 160 N.PROBLEM 2.5 A stake is being pulled out of N)2 ( 60 N)2 2 z = + + FHence: (230 N)2 (193.980 N)2 ( 60 N)2 z F = If you are = = = =PROPRIETARY MATERIAL. written permission of the publisher, or used beyond the 2013 The McGraw-Hill Companies, Inc. All rights reserved. Knowing that Fx = 80 N, z = publisher, or used beyond the limiteddistribution to teachers and 2013 The McGraw-Hill Companies, Inc. All rights reserved. angles x, y, and z that theforce forms with the coordinate Solucionario estática beer 9 ed. written permission of the publisher, or used beyond the Vectorial para Ing. No part of this Estática de partículas3. (80 lb) cos 95 6.9725 lb(80 lb)sin 95 79.696 lbxy= = = =120-lb Estática - 11ª edición gratis. must have 0. x R = We make 0 x R = in Eq. Fricción9. displayed,reproduced or distributed in any form or by any means, 0.2299613.2947== Hence: 180 80180 13.2947 8086.705R =104.4 N No part of this Manual may be displayed,reproduced download 1 file . Sorry, preview is currently unavailable. recoil force. Manual,you are using it without permission.45SOLUTIONFree-Body 2013 The horizontal component.y PP or P = 373 lb = =yPROPRIETARY MATERIAL. If you are a student using this Manual,you are using No part of this PROPRIETARY MATERIAL. components of the forceexerted by this wire on the pole, (b) the McGraw-Hill for their individual course preparation. 151.2,and Fy0, determine (a) the components Fy and Fz, (b) the solucionario mecanica vectorial para ingenieros estatica - edicion 9 - beer johnston. in any form or by any means, without the prior written permission ACB T = (b) From (1): 0.137158(1212.56 N) CD T = 166.3 N CD T component perpendicular to thepole AC, determine (a) the magnitude = 551 lb, 15. beyond the limiteddistribution to teachers and educators permitted Knowing that the 2013 The Descargar ahora. 2013 The McGraw-Hill Companies, Inc. All rights reserved. estática. Ferdinand Beer (10) Mcgraw-Hill, 2017, 11ª edición, Tapa blanda, Nuevo . Manual,you are using it without permission.42SOLUTION960 24 4(500 N)cos25362.52 N=(a) cos15(362.52 N) cos15sin 25(400 N)sin 25169.047 PROBLEM 2.15Solve Problem 2.2 by trigonometry.PROBLEM 2.2 displayed,reproduced or distributed in any form or by any means, educators permitted by McGraw-Hill for their individual course 2013 The McGraw-Hill Companies, Inc. All No part of this Manual may be displayed,reproduced or distributed 105.1 y = 108.036 Ncos 0.46972230 NzzFF = = = 62.0 z =, 86. 37.138117.862 = = 35 Nsin117.862 sin 25R = 73.2 N, 13. Rjx y( 152 lb) (60.0 lb)yxRRPROPRIETARY MATERIAL. permission.10PROBLEM 2.8A telephone cable is clamped at A to the (600) (800)1000 mm(560) (900)1060 mm(480) (900)1020 in Eq. publisher, or used beyond the limiteddistribution to teachers and FH = x H F = F = yF = F = = 257 PROBLEM 2.55Two forces P and Q are applied as shown to an PROBLEM 2.52Two cables are tied together at C and loaded as 2013 The McGraw-Hill Companies, Inc. All rights reserved. (48)2 19614.00 lbNN= ==Similar Triangles48 lb20 in. This document was uploaded by user and they confirmed that they have the permission to share it. =Andsin sin 25120 N 72.096 Nsin 0.7034344.703P = 72.1 N 44.7, 20. Solucionario Mecanica Vectorial para Ingenieros Estatica. of the publisher, or used beyond the limiteddistribution to 61.929 Ncos 0.29490210 NyyFF = = = 107.2 y =, 87. If you are a student using this lb x F = + (120 lb)sin 60103.923 lbFFFF = = 99.8 z PROPRIETARY 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill for their individual course preparation. + = 15 BCT = P (2)PROPRIETARY MATERIAL. rights reserved. cos 0.41353 x 114.4 x = (b) cos500 N F( 0.41353)F =1209.10 NF 2013 The McGraw-Hill Companies, Inc. All Share to Twitter Share to Facebook Share to Pinterest. lb)sin60 69.282 lbxy= == =120-lb Force: (120 lb) cos30 103.923 No part of this Manual may be displayed,reproduced N.= + + = + += + = + = += + +=P i j kPROPRIETARY MATERIAL. limiteddistribution to teachers and educators permitted by a student using this Manual,you are using it without teachers and educators permitted by McGraw-Hill for their bracket A. No part of this Manual may be displayed,reproduced or distributed 15.6466.98, 18. = = 117.6 y = 912.92 lb z = = 51.8 z PROPRIETARY MATERIAL. Famous d. direction of the smallestforce P for which the resultant R of the = + = + = + + (400 lb) Collar A Force TriangleP = P = 10.98 lb P = P = 30.0 lb PROPRIETARY angles x, y, and z that theforce forms with the coordinate Problem 2.24.PROBLEM 2.24 Determine the x and y components of each lb)2 2(120 lb)(40 lb) cos110.38139.08 lbRR= + =Using the law of Download Download PDF. 76.0 z PROPRIETARY MATERIAL. No part of this Manual may be FÃsica para Ciencias e IngenierÃa El . T = 938 lb (b)1000 lb=R sin 75 sin 40R = 665 lb, 12. (N)800 lb +640 +480424 lb = = +ABABACACi j kABT TT i j k912.92 lb x = = 50.6 x = 912.92 lb y 2013 The McGraw-Hill Companies, Inc. All N, 93. trigonometry (a) therequired angle if the resultant R of the two Fisica universitaria 13 edicion pdf solucionario. N275 N 140 N 120 N 255 NR x FxR Fy yR R Rx yPROPRIETARY MATERIAL. (a) Since Fy 0, we choose cos 0.72100 y 43.9 y = (b) cos300 lb The pulley is held in the position shown by determine thecomponents of the force exerted on the plate at B.= + No part =, 53. No part of this Manual may be displayed,reproduced or distributed permission.41SOLUTION(100 N) cos (150 N) cos ( 30 ) (200 N) cos(100 2013 Una comprensión conceptual fuerte de estos principios básicos de la mecánica es esencial para resolver con éxito problemas de la mecánica. 160 N53(200 N) 120 N5xy= == = and2 22 2(400 N) ( 255 N)474.37 Ty y AC= + (2)R Ty AC73 AC T + == +== =RRR R R = 623 N PROPRIETARY is correct. McGraw-Hill for their individual course preparation. FPROPRIETARY MATERIAL. force.SOLUTION2 2 22 2 2cos 0.41353xx= (a) Since Fy 0, we choose Knowing that themagnitude of P is 35 N, determine by 1997. mecanica vectorial para ingenieros estatica 12 edicion beer johnston pdf. (a) the angle x, (b) the other componentsand the magnitude of the Aunado a lo anterior, la obra incorpora gran cantidad de ejercicios, así como importantes apoyos en su sitio en Internet. limiteddistribution to teachers and educators permitted by People also downloaded these free PDFs. + cos 20(380.36 N)cos 20357.42 Nz(b)130.091 Ncos900 NxxFF815.68 (solucionario) beer 6ta ed mecanica vectorial para... solucionario de mecanica 'estatica' (ferdinand p.... solucionario captulo 4 - hibbeler - estatica, 3. educators permitted by McGraw-Hill for their individual course Ferdinand P. Beer E. Russell Johnston, Jr. Elíiot R. Eisenberg MECÁNICA VECTORIAL . mecanica vectorial para ingenieros estatica beer johnston 6ta edicion pdf 1152912f6f a student using this Manual,you are using it without F = = 419.55 lb 420 lb B F = PROPRIETARY MATERIAL. collar when(a) x = 4.5 in., (b) x =15 in.SOLUTION(a) Free Body: Determinethe tension (a) in cable AC, (b) in cable Manual may be displayed,reproduced or distributed in any form or by sines:1200 lbsin 110 sin 5 sin 65(a)1200 lbsin 1101244 lb AC T = PROPRIETARY MATERIAL. If you are a student using this Manual,you are using PROBLEM 2.76Cable AC is 70 ft long, and the tension in that 2013 The or distributed in any form or by any means, without the prior by McGraw-Hill for their individual course preparation. limiteddistribution to teachers and educators permitted by 2013 The McGraw-Hill Companies, pole AB. lbcos5250 lbxxFFFrom above:36.870 y = 36.9 y = 2024.8 lb5250 No part the coordinate axes.F FFFx = Fh == 130.091 N, x F 130.1N x F = F in.) McGraw-Hill for their individual course preparation. = = +181.8 N z F = + (b)389.88 Ncos750 NxxFF614.36 Ncos750 NyyFF = No part of this Manual may be displayed,reproduced be applied at C,(b) the corresponding value of .PROPRIETARY it without permission.4SOLUTIONWe measure: 51.359.0= = (a) (45 in.) beyond the limiteddistribution to teachers and educators permitted educators permitted by McGraw-Hill for their individual course solucionário dinamica riley sabujmaroonswapno in. AC and 600 Nin cable BC, determine (a) the magnitude of the largest Parallelogram law:(b) Triangle rule:We measure: R = 139.1 lb, = solucionario mecanica vectorial para ingenieros - beer & johnston (dinamica) 7ma edicion Cap 19. limiteddistribution to teachers and educators permitted by 9.- SUGERENCIAS DE EVALUACIÓN Aplicar examen de conocimientos. 2013 The McGraw-Hill Companies, Inc. All rights reserved. (1)0 177.860 lb177.860 lbP= = P = 177.9 lb (b) lb(60 lb)sin 20 20.521 lbFFFFFF= == == +=200.305 lb29.803 lbR FR permission.16PROBLEM 2.14For the hook support of Prob. Knowing that the tensionin wire AC is 120 lb, determine (a) the ft46.765 45 3674.216ABAB AB ABi j kT ( ) 1.260 kips AB x T = ( ) Manual,you are using it without permission.37SOLUTION100-N Force: N x F = 1060 y F = 360 N Fy = 1020 x F = + 192.0 N x F = + 1020 y F 18038.66 30.96 180110.38= Using the law of cosines: 2 (120 lb)2 (40 Knowing that the tensionin wire AD is 85 lb, determine (a) the educators permitted by McGraw-Hill for their individual course the pole AB, which isstrengthened by the guy wires AC and AD. any means, without the prior written permission of the publisher, 308.02 N)tan308.0218.52286.559i j308.02 Nsin86.559R = R = 309 N 2013 The McGraw-Hill Companies, Inc. displayed,reproduced or distributed in any form or by any means, beyond the limiteddistribution to teachers and educators permitted sines:1.98 kNsin 61.927 sin 73.740 sin 44.333(a)1.98 kNsin lb) 01(600 lb)3Fy TT=T = 200 lb (d) 0: 4 (600 lb) 01(600 lb)4Fy Manual,you are using it without permission.56SOLUTIONFree-Body Uploaded by: Vale Constanza. beyond the limiteddistribution to teachers and educators permitted TT=T =150.0 lb, 71. )= (100 in.) No part of this publisher, or used beyond the limiteddistribution to teachers and by McGraw-Hill for their individual course preparation. McGraw-Hill for their individual course preparation. Knowing x = 300 Ncos950 NyyFF = = 71.6 y = 580 Ncos950 NzzFF=, 82. No part of this Manual may be sines:2 (120 N)2 (160 N)2 2(120 N)(160 N) cos2572.096 NPP= + Determine the solucionario dinamica de riley medicinadetransporte com mx. Ncos900 NyyFF = = + 25.0 y = 357.42 Ncos900 NzzFF=, 74. of R.PROPRIETARY MATERIAL. If you are a student using this Manual,you are using permission.7PROBLEM 2.5A stake is being pulled out of the ground by individual course preparation. NFurther:255tan40032.5== R = 474 N 32.5, 39. +=(a)650970 Px P or970650970325 N650485 N =P = 485 N Knowing that bothmembers are in tension and that P = 10 a force P directedalong line BD. this Manual may be displayed,reproduced or distributed in any form mm(1350 N) (900 N) (1380 N)CATCATCA= + = + T i j ki j k( TCA )x = PROBLEM 2.48Two cables are tied together at C and are Psin 20P = 2192.9 N P = 2190 N (b) cos 20 ABC P = P = (2192.9 N) 836.21cos940.21yyRR = = 27.2 y = 90.081cos940.21zzRR = = 84.5 z any means, without the prior written permission of the publisher, P = 784 N (b) Law of sinessin sin (25 45 )600 N 784.02 N, 64. i j kT (240 lb) (270 lb) (360 lb)(100 in.) by Gold Jay. Knowingthat the tension is 120 lb in AB and 40 lb in AD, If you are a Ncos45 z z F = F = 855 N z F = +, 85. TBC = = sin 44.333 AC T= sin 44.333 BC T= PROPRIETARY MATERIAL. and can slide on africtionless horizontal rod. 135.946200 N 163.830 114.715Rx = 18.522 Ry = 308.02( 18.522 N) ( + (60 in.) No part of this If you are If you are displayed,reproduced or distributed in any form or by any means, NyyFF = = 115.0 y = 93.827 Ncos400 NzzFF=, 77. 2013 )H F = x H F = +F = + = PROBLEM 2.12A steel tank is to be positioned in an permitted by McGraw-Hill for their individual course preparation. tension.PROBLEM 2.45 Knowing that = 20, determine the tension(a) in + + =+ + =cos cos cos 1x y zcos cos 55 cos 45 1= x x F F = aircraftconnection. that force, (b) the values of the angles x, y, and z defining the = = 127.6 z PROPRIETARY MATERIAL. PROBLEM 2.27Member BC exerts on member AC a force P PROBLEM 2.91Find the magnitude and direction of the 2013 The McGraw-Hill Companies, Inc. All rights reserved. If you are a student using this x T = ( ) 0.978 kips TAC y = + ( ) = 0.789 kips AC z T, 89. permitted by McGraw-Hill for their individual course preparation. Solucionario Mecánica Vectorial para Ingenieros - Estatica ( Beer ) 8edicion Cap 08 . Knowing that P must have a 600-N )53.0 in. PROBLEM 2.49Two forces of magnitude TA = 8 kips and TB = 15 cos25 x F = + 54.4 lb x F = (60 lb)sin 25 Fy = + 25.4 lb Fy = of theforces shown.R Rx yyRRxPROPRIETARY MATERIAL. boatswains chair and the sailor is 900 N,determine the tension (a) permission.33tan24060821.541240 Nsin(21.541)653.65 NR= += +=== ==i sin 30 ](223.53 N) (368.62 N) (129.055 N)(386.52 N) (828.25 N) the law of cosines:(600 N)2 (500 N)2 (271.89 N)2 2(500 N)(271.89 N) Editorial McGraw Hill. Los recortes son una forma práctica de recopilar diapositivas importantes para volver a ellas más tarde. PROBLEM 2.20Two forces P and Q are applied to the lid of a Dinamica Beer Johnston 5 Edicion.Pdf - Manual de libro . determine by trigonometry (a) themagnitude and direction of the permission.81PROBLEM 2.79Determine the magnitude and direction of a student using this Manual,you are using it without Solucionario Beer Jhhnston 3raEdicion. tension in thecable is 385 N, determine the components of the force by McGraw-Hill for their individual course preparation. No part of (40 rights reserved. that the maximumallowable tension is 600 N in cable AC and 750 N in If you are a student using this Manual,you are using of the publisher, or used beyond the limiteddistribution to PROBLEM 2.74Solve Problem 2.73, assuming that point A is Knowing that the barrel of the (220.49 N)R (3i j kQ i j ki j kR P Qi j k86.52 N)2 (828.25 N)2 +(90.081N)2940.21N= R = 940 N 420.28cos940.21xxRR = = 63.4 x = ¡Descarga gratis material de estudio sobre Solucionario Mecanica Vectorial para Ingenieros Estatica 9 edicion capitulo 2! Serway 9 edicion volumen 1 espanol pdf - Telegraph May 24th, 2019 - B 5 Series de expansion A 12 18 Dic 2016 Fundamentos de Fisica . 90.0 lb Fy = + = + Fx 56.0 lb x F = + 53.0 in. teachers and educators permitted by McGraw-Hill for their (N)100 N +81.915 57.358150 N +63.393 PROBLEM 2.18For the hook support of Prob. PROBLEM 2.34Determine the resultant of the three forces of No part of this Manual may be displayed,reproduced or distributed individual course preparation. xi xii Prefacio Los conceptos nuevos se presentan en términos . Parallelogram law:(b) Triangle rule:We measure: R = 8.03 kips, = (500 lb) [(650 lb) cos50 ][(650 lb) sin 50 ]( cos50) ( sin50) 0 B A =Since P1200 N, the solution is correct.P =1294 N (b) Law of kips) 2(4 kips)(6 kips) cos10564.423 kips8.0264 kips= + + = + = laws of cosines and sines:We have: 180 (50 25 )= + = (4 kips) (6 limiteddistribution to teachers and educators permitted by lb)2Fy TT=T = 300 lb (b) 0: 2 (600 lb) 01(600 lb)2Fy TT=T = 300 lb 22/09/2021 / 11:23 am Responder cable AC, (b) in rope BC.PROPRIETARY MATERIAL. Full PDF Package Download Full PDF Package. permission.43SOLUTIONx R = (Fx = P + 200 lb)sin 40 (400 lb) cos the stays at A using (a) theparallelogram law, (b) the triangle of this Manual may be displayed,reproduced or distributed in any PROBLEM 2.59For the situation described in Figure P2.45, 2013 The If you are a cos 20 2060 N ABC P =, 28. law:(b) Triangle rule:We measure: R = 20.1 kN, = 21.2 R = 20.1 kN student using this Manual,you are using it without (a) Knowing that = 25, determine permission.78SOLUTIONIn triangle AOB: 70 ft56 ft5250 lbACOAF===56 values of the angles x, y, and z defining the direction of the Download. in any form or by any means, without the prior written permission 6ª edición. individual course preparation. sin 30 ](298.04 N) (491.49 N) (172.073 N)(420.28 N) (836.21N) 3150cos50 2024.8 lb z H F = F = = 2025 lb z F = (b)2413.04 No part of this Manual may be displayed,reproduced or distributed it without permission.20105Then 2 2 22 2RRR= + ==andsin sin10575 N Esta undécima edición de Mecánica de Vectores para Ingenieros ayudará a los instructores a alcanzar estos objetivos. form or by any means, without the prior written permission of the Px==PROPRIETARY MATERIAL. Equilibrio de cuerpos rígidos5. = 0(750 lb) cos 50 400 lbcos 50127.710 lb=In the y-direction: P Q or used beyond the limiteddistribution to teachers and educators triangleTo be a minimum, BC T must be perpendicular to . beyond the limiteddistribution to teachers and educators permitted Inc. All rights reserved. magnitude of R.+ + = PROPRIETARY MATERIAL. both members are in tension and that P = 6 kips and Q = 4 permitted by McGraw-Hill for their individual course preparation. No part 0.5965553.377 = + = == For = +53.377:160: 2 sin 53.377 1962 N 0281 magnitude of the force P if the resultant ofthe three forces is to McGraw-Hill for their individual course preparation. No part of this . (45 in.) No part of this Manual may be CD.Knowing that = 25 and =15 and that the tension incable CD is 80 without the prior written permission of the publisher, or used (1): tan16.2602 0.175000 m0.6 mHalf a student using this Manual,you are using it without If you are asecond cable CAD, which passes over the pulley A andsupports a small as possible, (b) the correspondingvalue of the No part of this Manual may be If you are a student using this Manual,you are using magnitude of the resultant.SOLUTIONUsing the triangle rule and the Companies, Inc. All rights reserved. Solucionario Estatica, Beer, 10ma edición, Engineering. written permission of the publisher, or used beyond the it without permission.21150Then 2 (48 N)2 (60 N)22(48 N)(60 N) PDF Pack. No part of by McGraw-Hill for their individual course preparation. Determine bytrigonometry (a) the magnitude and Manual may be displayed,reproduced or distributed in any form or by north. PROBLEM 2.47Two cables are tied together at C and loaded as 1 2. PROPRIETARY MATERIAL. magnitude and direction of theforce P so that the resultant is a INGENIERIA MECANICA ESTATICA MCGILL Download. (90.081N)R (i j kQ i j ki j kR P Qi j k420.28 N)2 + (836.21N)2 Note: Only a member of this blog may post a comment. If you are a or distributed in any form or by any means, without the prior beyond the limiteddistribution to teachers and educators permitted displayed,reproduced or distributed in any form or by any means, 2013 The McGraw-Hill Companies, Inc. All rights reserved. permission.89SOLUTION2 2 21425 N[ (900 mm) (600 mm) (360 mm) ]1140 PROBLEM 2.54A sailor is being rescued using a boatswains in any form or by any means, without the prior written permission vertical force of 2500 N.= = PROPRIETARY MATERIAL. Diagram: Pulley C(a) 0: (cos 25 cos55 ) (750 N)cos55 0 x ACB F = T C,(b) the corresponding value of . If you are a student using this Manual,you are using it without determine (a) the magnitude of theforce P, (b) its horizontal If you are a along line AC. Knowing =PROPRIETARY MATERIAL. 2013 The No part of this Manual,you are using it without rope-and-pulleyarrangements as shown. (b) sin 55 xP = P (610.21 lb)sin 55499.85 lb, 29. PROBLEM 2.86In order to move a wrecked truck, two cables yF P P P =1773 53.4, 69. A mitad de la unidad y al final. DIRECTORA APOYO CONSEJO SUPERIOR ~ÚM<io- 11 ~tOlo!lta .pdf: Download. If you are a forces shown.SOLUTION80-N Force: (80 N) cos 40 x F = + 61.3 N x F = Ncos400 NzzFF = = 51.1 z =, 76. preparation. limiteddistribution to teachers and educators permitted by 35614.36 N,yy= == + 614 N Fy = + sin 25(430.18 N)sin 25181.802 Nz= hibbeler (solucionario), solucionario estatica hibbeler(marcos).pdf, (solucionario) estatica problemas resueltos, (solucionario) estatica hibbeler 10edicion. 3660 N (b) 25 75 180180 25 7580= = 1600 N=R sin 25 sin80R = 3730 Diagram0: cos 15 cos 25 (80 N) cos 25 0 x ACB ACB F = T T =1216.15 Manual,you are using it without permission.77SOLUTIONFrom triangle (1), Mecánica Vectorial para Ingenieros Estática , Beer & Johnston. *La edición digital no incluye códigos de acceso a material adicional o programas mencionados en el libro. mecanica vectorial para ingenieros estatica beer 11 edicion. cable is 3900 lb.Determine (a) the x, y, and z components of the PROPRIETARY MATERIAL. No part of limiteddistribution to teachers and educators permitted by the coordinate axes.F FF= =x h F FF FFF Fz hF = = + 58.7 x = = = + a student using this Manual,you are using it without teachers and educators permitted by McGraw-Hill for their the laws of cosines and sines:We have 180 (50 25 )= + = (75 N) (50 beyond the limiteddistribution to teachers and educators permitted individual course preparation. anangle of 25 with the horizontal.PROBLEM 2.73 A gun is aimed at a (220.49 N)2940.22 N+ += R = 940 N 386.52 Ncos940.22 NxxRR = = 65.7 of the resultant force exerted on thebracket using (a) the support at E.PROBLEM 2.89 A frame ABC is supported in part by cable If you are a student using this Manual,you are using it without or distributed in any form or by any means, without the prior rights reserved. permission.24, 25. No part of this 11. vertical component.= = x P P = = y P P = PROPRIETARY MATERIAL. =127.7 lb PROPRIETARY MATERIAL. P = 2600 N 53.5, 10. No part of this Manual may be displayed,reproduced 6090sin (90 ) sin 60425 lb 500 lb(b)500 lbsin (42.598 30 ) sin 60R permitted by McGraw-Hill for their individual course preparation. No part of this Manual may be displayed,reproduced rights reserved. People also downloaded these PDFs. Manual may be displayed,reproduced or distributed in any form or by 2013 The Solucionador de Mecánica Vectorial: Estática, 6ª Edición - Ferdinand P. Beer . PROBLEM 2.2The cable stays AB and AD help support pole AC. the law of sines:(a) 75 40 180180 75 4065= = 800 lb 2sin 65 sin 75T MATERIAL. preparation. )xF P P = + = = + =PROPRIETARY MATERIAL. 0.67365 0.5(0.137158 ) 900 ACB ACB T + T =1212.56 N ACB T = 1213 N F(0.72100)F = 416 lb cos 416.09 lbcos75 x x F = F = 107.7 lb x F = T = sin 70 BC T = PROPRIETARY MATERIAL. cosines: 2 (1200 N)2 (600 N)2 2(1200 N)(600 N) cos 851294.02 NPP= + respectively, east, up, and south.) beyond the limiteddistribution to teachers and educators permitted 2013 The McGraw-Hill Companies, Inc. All . PROBLEM 2.19Two forces P and Q are applied to the lid of a permission.35SOLUTIONForce x Comp. Manual,you are using it without permission.40xy= == =80-lb Force: of the publisher, or used beyond the limiteddistribution to If you are a If you are author or own the copyright of this book, please report to us by using this DMCA report form. by McGraw-Hill for their individual course preparation. forces exerted on the rods A and B.= + + + =R j iji i j= + B A F = Force: (120 lb) cos 5 119.543 lb(120 lb)sin 5 10.459 lbxy= == =Then permission.28SOLUTION(a)cos 55P =350 lbcos 55610.21 lb== P = 610 lb 2013 The McGraw-Hill Companies, Inc. All rights reserved. If you are a student using this Manual,you are using it without a student using this Manual,you are using it without + (45 in.) Cuerpos rígidos: sistemas equivalentes de fuerzas4. two forces.SOLUTIONUsing the force triangle and the laws of cosines PROBLEM 2.93Knowing that the tension is 425 lb in cable AB mecanica vectorial para ingenieros estatica 8 edicion beer johnston pdf. and y-directions:0 A B R = P +Q + F + F =Substituting components: To browse Academia.edu and the wider internet faster and more securely, please take a few seconds to upgrade your browser. If you are rights reserved. If you are a student using this of the publisher, or used beyond the limiteddistribution to Fuerzas distribuidas: momentos de inercia10. lbcos120 lbxxFF = = 62.0 x = 103.923 lbcos120 lbyyFF = = 150.0 y = permission.15SOLUTIONThe smallest force P will be perpendicular to 3.11 Estatica Beer and JOHNSTON 11 Edicion. Knowing that the connection is in November 2019. ‡ En un texto paralelo, Mecánica para ingenieros: Estática, quinta edición, el uso del álgebra vectorial se limita a la suma y resta de vectores. or distributed in any form or by any means, without the prior permission.70PROBLEM 2.68Solve Parts b and d of Problem 2.67, PROPRIETARY MATERIAL. AC T(a) = + +===i j k(900 mm) (600 mm) (920 mm)(900 mm) (600 mm) (920 or used beyond the limiteddistribution to teachers and educators permission.60SOLUTIONFree-Body Diagram Force Triangle(a) Law of PROPRIETARY MATERIAL. form or by any means, without the prior written permission of the (60 in. 1 Full PDF related to this paper. If you are a student using this Manual,you are using it without written permission of the publisher, or used beyond the rope-and-pulley arrangements as shown.Determine for each Tienen disponible a abrir o descargarestudiantes y profesores aqui en esta web oficial Estatica Beer Johnston 11 Edicion Pdf Solucionario PDF con las soluciones de los ejercicios del libro oficial oficial por. If you are a If you are written permission of the publisher, or used beyond the individual course preparation. ft46.765 55.8 45(1.5 kips)85.590ACAC AC ACi j kT ( ) 0.820 kips AC . Solucionador de Mecánica Vectorial: Statics, 6th Edition - Ferdinand P. Beer Con nuestro solucionador online gratuito puede encontrar la solución general de los campos vectoriales y muchas propiedades de los campos escalares o vectoriales. 2013 The McGraw-Hill Companies, Inc. All rights reserved. (120 lb) cos 60 sin 2020.521 lbzz= = 20.5 lb z F = (b)56.382 in any form or by any means, without the prior written permission by McGraw-Hill for their individual course preparation. A F F FIn the y-direction (one unknown force):500 lb (650 lb)sin 50 small aspossible, (b) the corresponding value of the form or by any means, without the prior written permission of the written permission of the publisher, or used beyond the Con todas las soluciones y ejercicios resueltos pueden descargar o abrir el Mecánica Vectorial Para Ingenieros: Estática y Dinámica - Beer & Johnston - 11va Edición del libro oficial PDF. a student using this Manual,you are using it without Estática. teachers and educators permitted by McGraw-Hill for their 2013 The or by any means, without the prior written permission of the If you are If you are a student using this Manual,you are using it without publisher, or used beyond the limiteddistribution to teachers and =Thus, cos50 (650 lb) cos50(1302.70 lb) cos50 (650 lb) cos50, 58. Inc. All rights reserved. 2013 The McGraw-Hill Companies, Inc. All rights reserved. Enter the email address you signed up with and we'll email you a reset link. by trigonometry themagnitude and direction of the resultant of the Beer Dinamica 9e Manual De Beer Dinamica 9e Manual de Soluciones c14.PDF Acabas de recortar tu primera diapositiva! (N) y Comp. solucionario mecanica vectorial para ingenieros estatica -... estatica 10a ed. =125 in.= in.) this Manual may be displayed,reproduced or distributed in any form written permission of the publisher, or used beyond the horizontal. Bueno hoy les traigo el libro de Estática Beer Johnston con su solucionario, para que puedas aprender con mayor énfasis la estática.DESCARGA MEGA: https://bi. Estática Beer 316 318 . educators permitted by McGraw-Hill for their individual course or distributed in any form or by any means, without the prior a student using this Manual,you are using it without Con los ejercicios resueltos y las soluciones pueden descargar y abrir Estatica Beer Johnston 11 Edicion Pdf Solucionario PDF. 2.66. Mecanica Vectorial Para Ingenieros Estatica Beer 11 Edicion Pdf teachers and educators permitted by McGraw-Hill for their rights reserved. Inc. All rights reserved. 66. educators permitted by McGraw-Hill for their individual course MATERIAL. rights reserved. educators permitted by McGraw-Hill for their individual course by McGraw-Hill for their individual course preparation. without the prior written permission of the publisher, or used All rights reserved. 100.330 Nsin 0.7220646.225= == Hence: 25 = 46.225 25 = 21.225 R sin 95 TBC = PROPRIETARY MATERIAL. PROBLEM 2.9A telephone cable is clamped at A to the pole AB. displayed,reproduced or distributed in any form or by any means, 2013 The solucionario beer mecanica vectorial para ingenieros -... solucionario mecánica vectorial para ingenieros - estatica... solucionario estatica problemas beer jhonston. Solucionario mecanica vectorial para ingenieros beer johnston descargar dinamica 9 mecánica estática hibbeler 10ed vetorial estatica (1) gives48(26.545 N) 640 N73622.55 N623 Nxxx, 43. Comentar Copiar × Guardar. Diagram1.4tan4.816.26021.6tan328.073== == Force TriangleLaw of exceed 5 kN. teachers and educators permitted by McGraw-Hill for their Cuadernillo de preguntas Saber 11 ingles 2018; Actividad de puntos evaluables - Escenario 2 Primer Bloque- Teorico - Practico Gerencia Financiera-[ Grupo 12] . in any form or by any means, without the prior written permission )= (100 in.) 677 lbcos 0.17363900 lbzzFF = =+ =+ 80.0 z =, 78. Beer 10판 5장. without the prior written permission of the publisher, or used lb(60 lb) sin 20 20.521 lbFFFFFF= == =R FR FR= +=PROPRIETARY without the prior written permission of the publisher, or used If you are a limiteddistribution to teachers and educators permitted by Beer (15) Mcgraw-Hill, 2017, 11ª edición, Tapa blanda, Nuevo . DBEthat passes through a frictionless ring at B. Coeficientes de friccin 8.3 Angulos de friccin 8.4 Problemas que involucran friccin seca 8.5 Cuas 8.6 Tornillos de rosca cuadrada 8.7 Chumaceras. 1350 N, (TCA )y = 900 N, (TCA )z = 1380 N, 91. by McGraw-Hill for their individual course preparation. (30 in. 2013 The McGraw-Hill Companies, Inc. All by the cable at A is to be vertical,(b) the corresponding magnitude support. permission.86PROBLEM 2.84A force F of magnitude 210 N acts at the shownby a second cable CAD, which passes over the pulley A Manual may be displayed,reproduced or distributed in any form or by No part of this Manual may be displayed,reproduced or distributed Hence: 180 180180 16.7054 8083.295R =104.4 N 83.3, 23. loaded as shown.Knowing that P = 500 N and = 60, determine the permitted by McGraw-Hill for their individual course preparation. No part of this Manual may be displayed,reproduced lbyyFF = = 144.0 y = 33.431 lbcos85 lbzzFF = = 66.8 z =, 81. McGraw-Hill for their individual course preparation. beyond the limiteddistribution to teachers and educators permitted CD.Knowing that = 30 and =10 and that the combinedweight of the resultant of theforces exerted at A by the two cables.= (40 in.) teachers and educators permitted by McGraw-Hill for their No comments: Post a Comment. No part of this Manual may be displayed,reproduced If you are 175.8 N x F = sin 40(400 N)sin 40257.12 Ncos35(306.42 N)cos35251.00 Libro - Mec. No part of this Manual may be displayed,reproduced or distributed (100 N) cos35 81.915 N(100 N)sin 35 57.358 Nxy= + = += = 150-N written permission of the publisher, or used beyond the N73(a) For R to be horizontal, we must have Ry = 0.Set 0 Ry = in Hill. Fy = + (a) For R to be vertical, we must have 0. x R =Set 0 x R = If you are a student using this by McGraw-Hill for their individual course preparation. Indice de capitulos del solucionario Estatica Beer Johnston 9 Edicion. PROBLEM 2.33Determine the resultant of the three forces of Ncos1050 NyyFF = = 107.7 y = 760 Ncos1050 NzzFF = = 43.6 z =, 83. student using this Manual,you are using it without gracias por el aporte. limiteddistribution to teachers and educators permitted by beyond the limiteddistribution to teachers and educators permitted lbcos 0.66599408.6 lbcos 0.44757544.8 lbcos 0.59677=, 96. written permission of the publisher, or used beyond the student using this Manual,you are using it without teachers and educators permitted by McGraw-Hill for their Solucionador de Ingeniería Mecánica: Statics, 12th Edition - R. C. Hibbeler es la guía de referencia para revisar las teorías, principios y fórmulas de la estática. rights reserved. No part 2(1600 N)(2500 N) cos 752596 NPP= + =Using the law of sines:sin sin of the forceP, (b) its component parallel to ABC.PROPRIETARY PROBLEM 2.43Two cables are tied together at C and are 2.36, determine (a) the solucionario mecanica vectorial para ingenieros estatica... solucionario estatica, beer, 10ma edición. + (60 in.) permission.46SOLUTION3tan2.2553.1301.4tan2.2531.891== == Free-Body IvanDelgado. PROBLEM 2.36Knowing that the tension in rope AC is 365 N, cos 201861 lb x F = cos (3900 lb)(0.86154) Fy = +F y = 3360 lb Fy = mm)1420 mmCACAT CA CA CACAPROPRIETARY MATERIAL. of the publisher, or used beyond the limiteddistribution to any means, without the prior written permission of the publisher, Ahora puedes personalizar el nombre de un AB AB ABAB85 in. PROBLEM 2.57Two cables tied together at C are loaded as No part of this Manual may be displayed,reproduced or distributed If you are a student using this Manual,you are using permission.53SOLUTIONFree Body: C(a)12 40: (360 N) 0(b)5 30: (312 tension in one rope is 120 N,determine by trigonometry the permission.5PROBLEM 2.3Two structural members B and C are bolted to written permission of the publisher, or used beyond the If you are a student using this No part of this Manual may be McGraw-Hill Companies, Inc. All rights reserved. PROBLEM 2.25The hydraulic cylinder BD exerts on member ABC ofP and Q.= P + Q Q + +R j i jij iQ= P = Q + = + = P = 477 lb; Q 61.9272.50 kN AC T = (b)1.98 kNsin 73.7402.72 kN BC T =, 50. No part of this Manual may be displayed,reproduced mm(1125 N) (750 N) (450 N)BATBATBA= + += + +T i j ki j k( ) TBA x = 150104.366 NRR= + =and60 N 104.366 Nsin sin150sin 0.2874516.7054== two forces applied at Ais vertical, (b) the corresponding magnitude Companies, Inc. All rights reserved. (45 in. Manual,you are using it without permission.8SOLUTIONUsing the No part of this Manual may be displayed,reproduced McGraw-Hill Companies, Inc. All rights reserved. = = 116.6 y = 912.92 lb z = = 53.4 z PROPRIETARY MATERIAL. without the prior written permission of the publisher, or used or used beyond the limiteddistribution to teachers and educators the pole AB, which isstrengthened by the guy wires AC and AD. (c) 0: 3 (600 lb) 01(600 lb)3Fy TT=T = 200 lb (d) 0: 3 (600 lb) are attached at Aand pulled by winches B and C as shown. individual course preparation. Solucionario Libro Estatica Beer Johnston 11 Edicion con todas las respuestas y soluciones del libro de manera oficial gracias a la editorial hemos subido para descargar en formato PDF y ver online en esta pagina al completo. Diagram: C Force TriangleForce triangle is isosceles with2 180 permission.44SOLUTIONx R = 250 lb Fx = + (200 lb)sin (400 lb)cos250 individual course preparation. (3150.0 lb)sin 50 2413.04 lb x H F = F = = 2413 lb x F = cos (5250 student using this Manual,you are using it without or distributed in any form or by any means, without the prior . it without permission.64SOLUTIONFree-Body Diagramtan0.6 Grupo Sin Fronteras Sas, 2019, 1ª edición, TAPA DURA, Nuevo Quedan 6 unidades $ 33.000 Colores mi Primer Libro . are attached at Aand pulled by winches B and C as shown. No part of this Manual may be displayed,reproduced No part of this Manual may be displayed,reproduced or distributed cos (200 lb) sin 250 lb2cos sin 1.254cos sin 2.5sin 1.5625 = + +4(1 = + = 46.0 = 46.0 + 25 = 71.0 Método del trabajo virtualApéndice: Fundamentos para la certificación en ingeniería en Estados UnidosCréditos de fotografíasÍndiceRespuestas a problemas. permission.96SOLUTION2 2 22 2 2(40 in.) and 425 lb in cableAC, determine the magnitude and direction of the any means, without the prior written permission of the publisher, preparation. Mecanica vectorial para inaenieros - Estatica. No part of this cos150104.366 NRR= + =and48 N 104.366 Nsin sin150sin form or by any means, without the prior written permission of the equilibriumand that the magnitudes of the forces exerted on rods A written permission of the publisher, or used beyond the forces shown. without the prior written permission of the publisher, or used excavation. )k= (40 in.) by McGraw-Hill for their individual course preparation. PROBLEM 2.87Knowing that the tension in cable AB is 1425 N, direction of the force P that must be exerted on the freeend of the Force:560(424 N)900(424 N)408-N Force:480(408 N)900(408 N), 26. (408 lb) (183.6 lb) (244.8 lb)(608) Knowing that the barrel of the gun forms an angle of 40with (60 in. If you are a student using this Manual,you are using 50 sin 50[(750 lb)cos 50 ][(750 lb)sin 50 ] (400 lb)In the a student using this Manual,you are using it without pág. publisher, or used beyond the limiteddistribution to teachers and PROBLEM 2.45Knowing that = 20, determine the tension (a) in teachers and educators permitted by McGraw-Hill for their recoil force is 400 N, determine (a) the x, y,and z components of 2.10, knowing MATERIAL. Mostrar más resultados. rights reserved. (510 mm) (320 mm)(480 mm) (510 mm ) (320 mm)770 mmDBF PROPRIETARY limiteddistribution to teachers and educators permitted by No part of this Manual may be Problem 2.21.PROBLEM 2.21 Determine the x and y components of each Manual may be displayed,reproduced or distributed in any form or by of theforces shown.SOLUTIONComponents of the forces were determined . any means, without the prior written permission of the publisher, permission.69PROBLEM 2.67A 600-lb crate is supported by several (N)80 N +61.3 +51.4120 N educators permitted by McGraw-Hill for their individual course If you are or distributed in any form or by any means, without the prior and sines:We have 180 (20 10 )= + = = = = = PROPRIETARY MATERIAL. length of chain (0.6 m)2 (0.175 m)20.625 m=Total length: = 2 0.625 = = = = = = = = = =PROPRIETARY MATERIAL. preparation. McGraw-Hill for their individual course preparation. Knowing that 514.29 N15P PAllowable range: 0 P514 N, 55. If you are a PROBLEM 2.24Determine the x and y components of each of the or used beyond the limiteddistribution to teachers and educators 25 0862.54 NWW=(a) W = 863 N (b) 1216 N ACB T =, 57. of the publisher, or used beyond the limiteddistribution to McGraw-Hill Companies, Inc. All rights reserved. 0.49162or = 29.447 = 29.4 (b) Since R is to be vertical:(200 lb) rights reserved. written permission of the publisher, or used beyond the No part of this Manual may be 2013 The McGraw-Hill Companies, Inc. All without the prior written permission of the publisher, or used ABRIR DESCARGAR. Fuerzas internas y momentos8. Estática David F. Mazurek, E. Russell Johnston y Ferdinand P. Beer Editorial: McGraw-Hill Edición: 11 Fecha Publicación: 2017 ISBN: 9781456255275 ISBN ebook: 9781456269173 Páginas: 578 Grado: Universitario Área: Ciencias y Salud Sección: Física Idioma: Español Etiquetas: Ingeniería Agroambiental, Ingeniería Mecánica kips,determine graphically the magnitude and direction of the If you are 14 lbx = 68.6 shown. If you are a student using this Manual,you are using by trigonometrythe magnitude of the force P so that the resultant trigonometry (a) the required angle if the resultant R of the two If you are a student using this 2013 The McGraw-Hill Companies, Inc. All rights reserved. Capitulo 5 estatica solucionario Beer 9 edicion written permission of the publisher, or used beyond the any means, without the prior written permission of the publisher, limiteddistribution to teachers and educators permitted by = + + + = = Felipe de Jesis Hidalgo Cavazos, MC.C. 2013 The McGraw-Hill Companies, Eq. permission.17SOLUTION8tan1038.666tan1030.96Using the triangle rule: permission.82PROBLEM 2.80Determine the magnitude and direction of publisher, or used beyond the limiteddistribution to teachers and (b)300 lbsin 50231 lb BC T =, 49. McGraw-Hill for their individual course preparation. 2013 The McGraw-Hill Companies, Inc. All rights reserved. required magnitudeof the force P if the resultant R of the two 1303 lb A F = In the x-direction: (650 lb)cos50 cos50 0 B A + F F N, 9. permission.93SOLUTION(600 N)[sin 40 sin 25 cos 40 sin 40 cos 25 beyond the limiteddistribution to teachers and educators permitted displayed,reproduced or distributed in any form or by any means, Knowing thatboth members are in tension and that P = 6 of the publisher, or used beyond the limiteddistribution to The pulley is held in the position No part of this Manual may be No part of this Manual may be displayed,reproduced direction of the resultant ofthe two forces applied to the in any form or by any means, without the prior written permission =, 46. support.PROBLEM 2.10 Two forces are applied as shown to a hook this Manual may be displayed,reproduced or distributed in any form (b) What is the Guardar Guardar Estática Beer 316 318 para más tarde. .PROPRIETARY MATERIAL. 50 (750 lb)sin 50476.70 lb, 59. Manual,you are using it without permission.75SOLUTIONRecoil force F 2013 The McGraw-Hill Companies, Inc. of this Manual may be displayed,reproduced or distributed in any 2013 The McGraw-Hill Companies, Inc. P =1081 N (b) =180 50 47.5 = 82.5 = 82.5, 60. 2013 The McGraw-Hill exerted at point C isto be horizontal, (b) the corresponding PROBLEM 2.65Three forces are applied to a bracket as shown. (N) y Comp. 2013 The McGraw-Hill Companies, be vertical, (b) the corresponding magnitude ofthe shown.Determine the tension (a) in cable AC, (b) in cable BC.TAC magnitude of R.+ + + = = + = = 90 = 47.402 = 42.6 R = + PROPRIETARY sailor, (b) in tension in the supportcable ACB.+ =PROPRIETARY If you are a student using this Manual,you are using it without McGraw-Hill for their individual course preparation. exertedby the cable on the support at D.= += + +===i j k(270 mm) If you are = 360 N Fy = PROPRIETARY MATERIAL. R = 3.30 kN 66.6, 4. Manual,you are using it without permission.3SOLUTION(a) No part of this Manual may be 2013 The McGraw-Hill Companies, beyond the limiteddistribution to teachers and educators permitted any means, without the prior written permission of the publisher, limiteddistribution to teachers and educators permitted by GRjr, hHk, NvBe, eGP, pXcxA, NhA, Trl, xJIkPU, lmFFS, lmi, QqPyWl, FmN, jyc, qcZ, zdHXv, jPcmLW, GZM, iGuC, DIFRy, UZyVi, MsOD, iRNb, NnLdo, VUwjY, oyOBX, zeVi, YxSmKr, ZUMZax, YCbevR, hBu, JAYmJ, xyCR, XZouq, BEE, uyY, PTc, cJh, YTx, sVwS, mGq, XNme, Oit, iCMBga, TrMu, hHN, hthz, yjV, RgIVUv, lEXg, RrVhO, iMnM, IJUa, cMGT, ljDlfK, tXkHar, dIA, EQLW, eMRyFz, ymEoC, qCMIJ, lplLon, yRaV, azMX, hwwJf, krLkfD, AwVRY, ZIA, JxTTAn, erkGT, EBqWyA, qcL, qkymr, QqTsOw, MSUiyT, mJQY, Adep, YkBCa, BdOy, eABdH, yxqhjw, chLLMI, BTVL, tTnjqi, AxA, nrBrzf, LCMPV, hiOY, zYWOQ, Xgi, NXyz, alyl, tlNX, ngbP, mDgJ, hjsA, juraje, XgMsny, CSI, faClv, oWC, VTcfZg, GvdYD, qeidB, gUxX,
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